Solve for x
x = \frac{40}{3} = 13\frac{1}{3} \approx 13.333333333
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6x=88-8
Subtract 8 from both sides.
6x=80
Subtract 8 from 88 to get 80.
x=\frac{80}{6}
Divide both sides by 6.
x=\frac{40}{3}
Reduce the fraction \frac{80}{6} to lowest terms by extracting and canceling out 2.
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