Solve for x
x=-\frac{5y}{6}+\frac{4}{3}
Solve for y
y=\frac{8-6x}{5}
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6x=8-5y
Subtract 5y from both sides.
\frac{6x}{6}=\frac{8-5y}{6}
Divide both sides by 6.
x=\frac{8-5y}{6}
Dividing by 6 undoes the multiplication by 6.
x=-\frac{5y}{6}+\frac{4}{3}
Divide 8-5y by 6.
5y=8-6x
Subtract 6x from both sides.
\frac{5y}{5}=\frac{8-6x}{5}
Divide both sides by 5.
y=\frac{8-6x}{5}
Dividing by 5 undoes the multiplication by 5.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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