Solve 6x+45-8y=0

$$6 x + 45 - 8 y = 0$$

Solve for x

$$x=\frac{4y}{3}-\frac{15}{2}$$

Steps for Solving Linear Equation

Subtract 45 from both sides. Anything subtracted from zero gives its negation.

$$6x-8y=-45$$

Add 8y to both sides.

$$6x=-45+8y$$

The equation is in standard form.

$$6x=8y-45$$

Divide both sides by 6.

$$\frac{6x}{6}=\frac{8y-45}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$x=\frac{8y-45}{6}$$

Divide -45+8y by 6.

$$x=\frac{4y}{3}-\frac{15}{2}$$

Solve for y

$$y=\frac{3x}{4}+\frac{45}{8}$$

Steps for Solving Linear Equation

Subtract 6x from both sides. Anything subtracted from zero gives its negation.

$$45-8y=-6x$$

Subtract 45 from both sides.

$$-8y=-6x-45$$

Divide both sides by -8.

$$\frac{-8y}{-8}=\frac{-6x-45}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$y=\frac{-6x-45}{-8}$$

Divide -6x-45 by -8.

$$y=\frac{3x}{4}+\frac{45}{8}$$