Solve for x
x=-\frac{y}{2}-\frac{z}{3}+\frac{3}{2}
Solve for y
y=-\frac{2z}{3}-2x+3
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6x+2z=9-3y
Subtract 3y from both sides.
6x=9-3y-2z
Subtract 2z from both sides.
6x=9-2z-3y
The equation is in standard form.
\frac{6x}{6}=\frac{9-2z-3y}{6}
Divide both sides by 6.
x=\frac{9-2z-3y}{6}
Dividing by 6 undoes the multiplication by 6.
x=-\frac{y}{2}-\frac{z}{3}+\frac{3}{2}
Divide 9-3y-2z by 6.
3y+2z=9-6x
Subtract 6x from both sides.
3y=9-6x-2z
Subtract 2z from both sides.
3y=9-2z-6x
The equation is in standard form.
\frac{3y}{3}=\frac{9-2z-6x}{3}
Divide both sides by 3.
y=\frac{9-2z-6x}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{2z}{3}-2x+3
Divide 9-6x-2z by 3.
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