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6w^{2}-5w=0
Subtract 5w from both sides.
w\left(6w-5\right)=0
Factor out w.
w=0 w=\frac{5}{6}
To find equation solutions, solve w=0 and 6w-5=0.
6w^{2}-5w=0
Subtract 5w from both sides.
w=\frac{-\left(-5\right)±\sqrt{\left(-5\right)^{2}}}{2\times 6}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 6 for a, -5 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
w=\frac{-\left(-5\right)±5}{2\times 6}
Take the square root of \left(-5\right)^{2}.
w=\frac{5±5}{2\times 6}
The opposite of -5 is 5.
w=\frac{5±5}{12}
Multiply 2 times 6.
w=\frac{10}{12}
Now solve the equation w=\frac{5±5}{12} when ± is plus. Add 5 to 5.
w=\frac{5}{6}
Reduce the fraction \frac{10}{12} to lowest terms by extracting and canceling out 2.
w=\frac{0}{12}
Now solve the equation w=\frac{5±5}{12} when ± is minus. Subtract 5 from 5.
w=0
Divide 0 by 12.
w=\frac{5}{6} w=0
The equation is now solved.
6w^{2}-5w=0
Subtract 5w from both sides.
\frac{6w^{2}-5w}{6}=\frac{0}{6}
Divide both sides by 6.
w^{2}-\frac{5}{6}w=\frac{0}{6}
Dividing by 6 undoes the multiplication by 6.
w^{2}-\frac{5}{6}w=0
Divide 0 by 6.
w^{2}-\frac{5}{6}w+\left(-\frac{5}{12}\right)^{2}=\left(-\frac{5}{12}\right)^{2}
Divide -\frac{5}{6}, the coefficient of the x term, by 2 to get -\frac{5}{12}. Then add the square of -\frac{5}{12} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
w^{2}-\frac{5}{6}w+\frac{25}{144}=\frac{25}{144}
Square -\frac{5}{12} by squaring both the numerator and the denominator of the fraction.
\left(w-\frac{5}{12}\right)^{2}=\frac{25}{144}
Factor w^{2}-\frac{5}{6}w+\frac{25}{144}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(w-\frac{5}{12}\right)^{2}}=\sqrt{\frac{25}{144}}
Take the square root of both sides of the equation.
w-\frac{5}{12}=\frac{5}{12} w-\frac{5}{12}=-\frac{5}{12}
Simplify.
w=\frac{5}{6} w=0
Add \frac{5}{12} to both sides of the equation.