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6u^{2}+18u=0
Add 18u to both sides.
u\left(6u+18\right)=0
Factor out u.
u=0 u=-3
To find equation solutions, solve u=0 and 6u+18=0.
6u^{2}+18u=0
Add 18u to both sides.
u=\frac{-18±\sqrt{18^{2}}}{2\times 6}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 6 for a, 18 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
u=\frac{-18±18}{2\times 6}
Take the square root of 18^{2}.
u=\frac{-18±18}{12}
Multiply 2 times 6.
u=\frac{0}{12}
Now solve the equation u=\frac{-18±18}{12} when ± is plus. Add -18 to 18.
u=0
Divide 0 by 12.
u=-\frac{36}{12}
Now solve the equation u=\frac{-18±18}{12} when ± is minus. Subtract 18 from -18.
u=-3
Divide -36 by 12.
u=0 u=-3
The equation is now solved.
6u^{2}+18u=0
Add 18u to both sides.
\frac{6u^{2}+18u}{6}=\frac{0}{6}
Divide both sides by 6.
u^{2}+\frac{18}{6}u=\frac{0}{6}
Dividing by 6 undoes the multiplication by 6.
u^{2}+3u=\frac{0}{6}
Divide 18 by 6.
u^{2}+3u=0
Divide 0 by 6.
u^{2}+3u+\left(\frac{3}{2}\right)^{2}=\left(\frac{3}{2}\right)^{2}
Divide 3, the coefficient of the x term, by 2 to get \frac{3}{2}. Then add the square of \frac{3}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
u^{2}+3u+\frac{9}{4}=\frac{9}{4}
Square \frac{3}{2} by squaring both the numerator and the denominator of the fraction.
\left(u+\frac{3}{2}\right)^{2}=\frac{9}{4}
Factor u^{2}+3u+\frac{9}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(u+\frac{3}{2}\right)^{2}}=\sqrt{\frac{9}{4}}
Take the square root of both sides of the equation.
u+\frac{3}{2}=\frac{3}{2} u+\frac{3}{2}=-\frac{3}{2}
Simplify.
u=0 u=-3
Subtract \frac{3}{2} from both sides of the equation.