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2\left(3tz-5z+6t-10\right)
Factor out 2.
z\left(3t-5\right)+2\left(3t-5\right)
Consider 3tz-5z+6t-10. Do the grouping 3tz-5z+6t-10=\left(3tz-5z\right)+\left(6t-10\right), and factor out z in the first and 2 in the second group.
\left(3t-5\right)\left(z+2\right)
Factor out common term 3t-5 by using distributive property.
2\left(3t-5\right)\left(z+2\right)
Rewrite the complete factored expression.