Solve 6t-43t^2-15

$$6 t - 43 t ^ { 2 } - 15$$

Differentiate w.r.t. t

$$6-86t$$

Steps Using Derivative Rule for Sum

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$6t^{1-1}+2\left(-43\right)t^{2-1}$$

Subtract 1 from 1.

$$6t^{0}+2\left(-43\right)t^{2-1}$$

Multiply 2 times -43.

$$6t^{0}-86t^{2-1}$$

Subtract 1 from 2.

$$6t^{0}-86t^{1}$$

For any term t, t^{1}=t.

$$6t^{0}-86t$$

For any term t except 0, t^{0}=1.

$$6\times 1-86t$$

For any term t, t\times 1=t and 1t=t.

$$6-86t$$

Evaluate

$$-43t^{2}+6t-15$$