Solve 6n+1+3n

$$6 n + 1 + 3 n$$

Differentiate w.r.t. n

$$9$$

Steps Using Derivative Rule for Sum

Combine 6n and 3n to get 9n.

$$\frac{\mathrm{d}}{\mathrm{d}n}(9n+1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$9n^{1-1}$$

Subtract 1 from 1.

$$9n^{0}$$

For any term t except 0, t^{0}=1.

$$9\times 1$$

For any term t, t\times 1=t and 1t=t.

$$9$$

Evaluate

$$9n+1$$

Solution Steps

Combine 6n and 3n to get 9n.

$$9n+1$$