Solve 6cy-30^2-(y-3)-15=0

$$6 c y - 30 ^ { 2 } - ( y - 3 ) - 15 = 0$$

Solve for c

$$c=\frac{1}{6}+\frac{152}{y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Calculate 30 to the power of 2 and get 900.

$$6cy-900-\left(y-3\right)-15=0$$

To find the opposite of y-3, find the opposite of each term.

$$6cy-900-y+3-15=0$$

Add -900 and 3 to get -897.

$$6cy-897-y-15=0$$

Subtract 15 from -897 to get -912.

$$6cy-912-y=0$$

Add 912 to both sides. Anything plus zero gives itself.

$$6cy-y=912$$

Add y to both sides.

$$6cy=912+y$$

The equation is in standard form.

$$6yc=y+912$$

Divide both sides by 6y.

$$\frac{6yc}{6y}=\frac{y+912}{6y}$$

Dividing by 6y undoes the multiplication by 6y.

$$c=\frac{y+912}{6y}$$

Divide y+912 by 6y.

$$c=\frac{1}{6}+\frac{152}{y}$$

Solve for y

$$y=\frac{912}{6c-1}$$

$$c\neq \frac{1}{6}$$

Steps for Solving Linear Equation

Calculate 30 to the power of 2 and get 900.

$$6cy-900-\left(y-3\right)-15=0$$

To find the opposite of y-3, find the opposite of each term.

$$6cy-900-y+3-15=0$$

Add -900 and 3 to get -897.

$$6cy-897-y-15=0$$

Subtract 15 from -897 to get -912.

$$6cy-912-y=0$$

Add 912 to both sides. Anything plus zero gives itself.

$$6cy-y=912$$

Combine all terms containing y.

$$\left(6c-1\right)y=912$$

Divide both sides by 6c-1.

$$\frac{\left(6c-1\right)y}{6c-1}=\frac{912}{6c-1}$$

Dividing by 6c-1 undoes the multiplication by 6c-1.

$$y=\frac{912}{6c-1}$$