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c\left(6c+24\right)=0
Factor out c.
c=0 c=-4
To find equation solutions, solve c=0 and 6c+24=0.
6c^{2}+24c=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
c=\frac{-24±\sqrt{24^{2}}}{2\times 6}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 6 for a, 24 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
c=\frac{-24±24}{2\times 6}
Take the square root of 24^{2}.
c=\frac{-24±24}{12}
Multiply 2 times 6.
c=\frac{0}{12}
Now solve the equation c=\frac{-24±24}{12} when ± is plus. Add -24 to 24.
c=0
Divide 0 by 12.
c=-\frac{48}{12}
Now solve the equation c=\frac{-24±24}{12} when ± is minus. Subtract 24 from -24.
c=-4
Divide -48 by 12.
c=0 c=-4
The equation is now solved.
6c^{2}+24c=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{6c^{2}+24c}{6}=\frac{0}{6}
Divide both sides by 6.
c^{2}+\frac{24}{6}c=\frac{0}{6}
Dividing by 6 undoes the multiplication by 6.
c^{2}+4c=\frac{0}{6}
Divide 24 by 6.
c^{2}+4c=0
Divide 0 by 6.
c^{2}+4c+2^{2}=2^{2}
Divide 4, the coefficient of the x term, by 2 to get 2. Then add the square of 2 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
c^{2}+4c+4=4
Square 2.
\left(c+2\right)^{2}=4
Factor c^{2}+4c+4. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(c+2\right)^{2}}=\sqrt{4}
Take the square root of both sides of the equation.
c+2=2 c+2=-2
Simplify.
c=0 c=-4
Subtract 2 from both sides of the equation.