Solve 6a^4-486

$$6 a ^ { 4 } - 486$$

Factor

$$6\left(a-3\right)\left(a+3\right)\left(a^{2}+9\right)$$

Solution Steps

Factor out 6.

$$6\left(a^{4}-81\right)$$

Consider a^{4}-81. Rewrite a^{4}-81 as \left(a^{2}\right)^{2}-9^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).

$$\left(a^{2}-9\right)\left(a^{2}+9\right)$$

Consider a^{2}-9. Rewrite a^{2}-9 as a^{2}-3^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).

$$\left(a-3\right)\left(a+3\right)$$

Rewrite the complete factored expression. Polynomial a^{2}+9 is not factored since it does not have any rational roots.

$$6\left(a-3\right)\left(a+3\right)\left(a^{2}+9\right)$$

Evaluate

$$6\left(a^{4}-81\right)$$