Solve 6a+4c=38

$$6 a + 4 c = 38$$

Solve for a

$$a=\frac{19-2c}{3}$$

Steps for Solving Linear Equation

Subtract 4c from both sides.

$$6a=38-4c$$

Divide both sides by 6.

$$\frac{6a}{6}=\frac{38-4c}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$a=\frac{38-4c}{6}$$

Divide 38-4c by 6.

$$a=\frac{19-2c}{3}$$

Solve for c

$$c=\frac{19-3a}{2}$$

Steps for Solving Linear Equation

Subtract 6a from both sides.

$$4c=38-6a$$

Divide both sides by 4.

$$\frac{4c}{4}=\frac{38-6a}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$c=\frac{38-6a}{4}$$

Divide 38-6a by 4.

$$c=\frac{19-3a}{2}$$