Solve for F
F=\frac{5\left(x-2\right)}{3}
Solve for x
x=\frac{3F}{5}+2
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3F+7=8+5x-11
Combine 6F and -3F to get 3F.
3F+7=-3+5x
Subtract 11 from 8 to get -3.
3F=-3+5x-7
Subtract 7 from both sides.
3F=-10+5x
Subtract 7 from -3 to get -10.
3F=5x-10
The equation is in standard form.
\frac{3F}{3}=\frac{5x-10}{3}
Divide both sides by 3.
F=\frac{5x-10}{3}
Dividing by 3 undoes the multiplication by 3.
3F+7=8+5x-11
Combine 6F and -3F to get 3F.
3F+7=-3+5x
Subtract 11 from 8 to get -3.
-3+5x=3F+7
Swap sides so that all variable terms are on the left hand side.
5x=3F+7+3
Add 3 to both sides.
5x=3F+10
Add 7 and 3 to get 10.
\frac{5x}{5}=\frac{3F+10}{5}
Divide both sides by 5.
x=\frac{3F+10}{5}
Dividing by 5 undoes the multiplication by 5.
x=\frac{3F}{5}+2
Divide 3F+10 by 5.
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Limits
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