Solve 6-3mgeqm-2/3

$$6 - 3 m \geq m - \frac { 2 } { 3 }$$

Solve for m

$$m\leq \frac{5}{3}$$

Solution Steps

Subtract m from both sides.

$$6-3m-m\geq -\frac{2}{3}$$

Combine -3m and -m to get -4m.

$$6-4m\geq -\frac{2}{3}$$

Subtract 6 from both sides.

$$-4m\geq -\frac{2}{3}-6$$

Convert 6 to fraction \frac{18}{3}.

$$-4m\geq -\frac{2}{3}-\frac{18}{3}$$

Since -\frac{2}{3} and \frac{18}{3} have the same denominator, subtract them by subtracting their numerators.

$$-4m\geq \frac{-2-18}{3}$$

Subtract 18 from -2 to get -20.

$$-4m\geq -\frac{20}{3}$$

Divide both sides by -4. Since -4 is negative, the inequality direction is changed.

$$m\leq \frac{-\frac{20}{3}}{-4}$$

Express \frac{-\frac{20}{3}}{-4} as a single fraction.

$$m\leq \frac{-20}{3\left(-4\right)}$$

Multiply 3 and -4 to get -12.

$$m\leq \frac{-20}{-12}$$

Reduce the fraction \frac{-20}{-12} to lowest terms by extracting and canceling out -4.

$$m\leq \frac{5}{3}$$