Solve 6-3|-2-3|+(-8+|-8+3-4|:3)

$$6 - 3 | - 2 - 3 | + ( - 8 + | - 8 + 3 - 4 | : 3 )$$

Evaluate

$$-14$$

Solution Steps

Subtract 3 from -2 to get -5.

$$6-3|-5|-8+\frac{|-8+3-4|}{3}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -5 is 5.

$$6-3\times 5-8+\frac{|-8+3-4|}{3}$$

Multiply 3 and 5 to get 15.

$$6-15-8+\frac{|-8+3-4|}{3}$$

Subtract 15 from 6 to get -9.

$$-9-8+\frac{|-8+3-4|}{3}$$

Subtract 8 from -9 to get -17.

$$-17+\frac{|-8+3-4|}{3}$$

Add -8 and 3 to get -5.

$$-17+\frac{|-5-4|}{3}$$

Subtract 4 from -5 to get -9.

$$-17+\frac{|-9|}{3}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -9 is 9.

$$-17+\frac{9}{3}$$

Divide 9 by 3 to get 3.

$$-17+3$$

Add -17 and 3 to get -14.

$$-14$$

Factor

$$-14$$