Solve 6--4--3+4-6-{4*[7-2*(-8+6)]}=

$$6 - - 4 - - 3 + 4 - 6 - \{ 4 \cdot [ 7 - 2 \cdot ( - 8 + 6 ) ] \} =$$

Evaluate

$$-33$$

Solution Steps

The opposite of -4 is 4.

$$6+4-\left(-3\right)+4-6-4\left(7-2\left(-8+6\right)\right)$$

Add 6 and 4 to get 10.

$$10-\left(-3\right)+4-6-4\left(7-2\left(-8+6\right)\right)$$

The opposite of -3 is 3.

$$10+3+4-6-4\left(7-2\left(-8+6\right)\right)$$

Add 10 and 3 to get 13.

$$13+4-6-4\left(7-2\left(-8+6\right)\right)$$

Add 13 and 4 to get 17.

$$17-6-4\left(7-2\left(-8+6\right)\right)$$

Subtract 6 from 17 to get 11.

$$11-4\left(7-2\left(-8+6\right)\right)$$

Add -8 and 6 to get -2.

$$11-4\left(7-2\left(-2\right)\right)$$

Multiply 2 and -2 to get -4.

$$11-4\left(7-\left(-4\right)\right)$$

The opposite of -4 is 4.

$$11-4\left(7+4\right)$$

Add 7 and 4 to get 11.

$$11-4\times 11$$

Multiply 4 and 11 to get 44.

$$11-44$$

Subtract 44 from 11 to get -33.

$$-33$$

Factor

$$-33$$