Solve 6-sqrt{2x+5}=0

$$6 - \sqrt { 2 x + 5 } = 0$$

Solve for x

$$x = \frac{31}{2} = 15\frac{1}{2} = 15.5$$

Steps for Solving Radical Equations

Subtract 6 from both sides of the equation.

$$-\sqrt{2x+5}+6-6=-6$$

Subtracting 6 from itself leaves 0.

$$-\sqrt{2x+5}=-6$$

Divide both sides by -1.

$$\frac{-\sqrt{2x+5}}{-1}=-\frac{6}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$\sqrt{2x+5}=-\frac{6}{-1}$$

Divide -6 by -1.

$$\sqrt{2x+5}=6$$

Square both sides of the equation.

$$2x+5=36$$

Subtract 5 from both sides of the equation.

$$2x+5-5=36-5$$

Subtracting 5 from itself leaves 0.

$$2x=36-5$$

Subtract 5 from 36.

$$2x=31$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{31}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{31}{2}$$