Solve 6-{3-[-13+3*(-2)*2]*5}-[4-(-2)^3]+6

$$6 - \{ 3 - [ - 13 + 3 \cdot ( - 2 ) \cdot 2 ] \cdot 5 \} - [ 4 - ( - 2 ) ^ { 3 } ] + 6$$

Evaluate

$$-128$$

Solution Steps

Multiply 3 and -2 to get -6.

$$6-\left(3-\left(-13-6\times 2\right)\times 5\right)-\left(4-\left(-2\right)^{3}\right)+6$$

Multiply -6 and 2 to get -12.

$$6-\left(3-\left(-13-12\right)\times 5\right)-\left(4-\left(-2\right)^{3}\right)+6$$

Subtract 12 from -13 to get -25.

$$6-\left(3-\left(-25\times 5\right)\right)-\left(4-\left(-2\right)^{3}\right)+6$$

Multiply -25 and 5 to get -125.

$$6-\left(3-\left(-125\right)\right)-\left(4-\left(-2\right)^{3}\right)+6$$

The opposite of -125 is 125.

$$6-\left(3+125\right)-\left(4-\left(-2\right)^{3}\right)+6$$

Add 3 and 125 to get 128.

$$6-128-\left(4-\left(-2\right)^{3}\right)+6$$

Subtract 128 from 6 to get -122.

$$-122-\left(4-\left(-2\right)^{3}\right)+6$$

Calculate -2 to the power of 3 and get -8.

$$-122-\left(4-\left(-8\right)\right)+6$$

The opposite of -8 is 8.

$$-122-\left(4+8\right)+6$$

Add 4 and 8 to get 12.

$$-122-12+6$$

Subtract 12 from -122 to get -134.

$$-134+6$$

Add -134 and 6 to get -128.

$$-128$$

Factor

$$-128$$