Solve 6(-2)^4+(3-2)^3+14(-2)^2-(-2)-2

$$6 ( - 2 ) ^ { 4 } + ( 3 - 2 ) ^ { 3 } + 14 ( - 2 ) ^ { 2 } - ( - 2 ) - 2$$

Evaluate

$$153$$

Solution Steps

Calculate -2 to the power of 4 and get 16.

$$6\times 16+\left(3-2\right)^{3}+14\left(-2\right)^{2}-\left(-2\right)-2$$

Multiply 6 and 16 to get 96.

$$96+\left(3-2\right)^{3}+14\left(-2\right)^{2}-\left(-2\right)-2$$

Subtract 2 from 3 to get 1.

$$96+1^{3}+14\left(-2\right)^{2}-\left(-2\right)-2$$

Calculate 1 to the power of 3 and get 1.

$$96+1+14\left(-2\right)^{2}-\left(-2\right)-2$$

Add 96 and 1 to get 97.

$$97+14\left(-2\right)^{2}-\left(-2\right)-2$$

Calculate -2 to the power of 2 and get 4.

$$97+14\times 4-\left(-2\right)-2$$

Multiply 14 and 4 to get 56.

$$97+56-\left(-2\right)-2$$

Add 97 and 56 to get 153.

$$153-\left(-2\right)-2$$

The opposite of -2 is 2.

$$153+2-2$$

Add 153 and 2 to get 155.

$$155-2$$

Subtract 2 from 155 to get 153.

$$153$$

Factor

$$3^{2}\times 17$$