Solve 6(-1)^4-4(-1)^3+2(-1)^2-1-11+10=

$$6 ( - 1 ) ^ { 4 } - 4 ( - 1 ) ^ { 3 } + 2 ( - 1 ) ^ { 2 } - 1 - 11 + 10 =$$

Evaluate

$$10$$

Solution Steps

Calculate -1 to the power of 4 and get 1.

$$6\times 1-4\left(-1\right)^{3}+2\left(-1\right)^{2}-1-11+10$$

Multiply 6 and 1 to get 6.

$$6-4\left(-1\right)^{3}+2\left(-1\right)^{2}-1-11+10$$

Calculate -1 to the power of 3 and get -1.

$$6-4\left(-1\right)+2\left(-1\right)^{2}-1-11+10$$

Multiply 4 and -1 to get -4.

$$6-\left(-4\right)+2\left(-1\right)^{2}-1-11+10$$

The opposite of -4 is 4.

$$6+4+2\left(-1\right)^{2}-1-11+10$$

Add 6 and 4 to get 10.

$$10+2\left(-1\right)^{2}-1-11+10$$

Calculate -1 to the power of 2 and get 1.

$$10+2\times 1-1-11+10$$

Multiply 2 and 1 to get 2.

$$10+2-1-11+10$$

Add 10 and 2 to get 12.

$$12-1-11+10$$

Subtract 1 from 12 to get 11.

$$11-11+10$$

Subtract 11 from 11 to get 0.

$$10$$

Factor

$$2\times 5$$