Solve 6(7/3)(7/3-1)=21-(7/3)

$$6 ( \frac { 7 } { 3 } ) ( \frac { 7 } { 3 } - 1 ) = 21 - ( \frac { 7 } { 3 } )$$

Verify

Solution Steps

Express 6\times \frac{7}{3} as a single fraction.

$$\frac{6\times 7}{3}\left(\frac{7}{3}-1\right)=21-\frac{7}{3}$$

Multiply 6 and 7 to get 42.

$$\frac{42}{3}\left(\frac{7}{3}-1\right)=21-\frac{7}{3}$$

Divide 42 by 3 to get 14.

$$14\left(\frac{7}{3}-1\right)=21-\frac{7}{3}$$

Convert 1 to fraction \frac{3}{3}.

$$14\left(\frac{7}{3}-\frac{3}{3}\right)=21-\frac{7}{3}$$

Since \frac{7}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$14\times \frac{7-3}{3}=21-\frac{7}{3}$$

Subtract 3 from 7 to get 4.

$$14\times \frac{4}{3}=21-\frac{7}{3}$$

Express 14\times \frac{4}{3} as a single fraction.

$$\frac{14\times 4}{3}=21-\frac{7}{3}$$

Multiply 14 and 4 to get 56.

$$\frac{56}{3}=21-\frac{7}{3}$$

Convert 21 to fraction \frac{63}{3}.

$$\frac{56}{3}=\frac{63}{3}-\frac{7}{3}$$

Since \frac{63}{3} and \frac{7}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{56}{3}=\frac{63-7}{3}$$

Subtract 7 from 63 to get 56.

$$\frac{56}{3}=\frac{56}{3}$$

Compare \frac{56}{3} and \frac{56}{3}.

$$\text{true}$$