Solve 6(4/3)^2-13*4/3+6=

$$6 ( \frac { 4 } { 3 } ) ^ { 2 } - 13 \times \frac { 4 } { 3 } + 6 =$$

Evaluate

$$-\frac{2}{3}\approx -0.666666667$$

Solution Steps

Calculate \frac{4}{3} to the power of 2 and get \frac{16}{9}.

$$6\times \frac{16}{9}-13\times \frac{4}{3}+6$$

Express 6\times \frac{16}{9} as a single fraction.

$$\frac{6\times 16}{9}-13\times \frac{4}{3}+6$$

Multiply 6 and 16 to get 96.

$$\frac{96}{9}-13\times \frac{4}{3}+6$$

Reduce the fraction \frac{96}{9} to lowest terms by extracting and canceling out 3.

$$\frac{32}{3}-13\times \frac{4}{3}+6$$

Express 13\times \frac{4}{3} as a single fraction.

$$\frac{32}{3}-\frac{13\times 4}{3}+6$$

Multiply 13 and 4 to get 52.

$$\frac{32}{3}-\frac{52}{3}+6$$

Since \frac{32}{3} and \frac{52}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{32-52}{3}+6$$

Subtract 52 from 32 to get -20.

$$-\frac{20}{3}+6$$

Convert 6 to fraction \frac{18}{3}.

$$-\frac{20}{3}+\frac{18}{3}$$

Since -\frac{20}{3} and \frac{18}{3} have the same denominator, add them by adding their numerators.

$$\frac{-20+18}{3}$$

Add -20 and 18 to get -2.

$$-\frac{2}{3}$$

Factor

$$-\frac{2}{3} = -0.6666666666666666$$