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6x^{2}+14x-28=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-14±\sqrt{14^{2}-4\times 6\left(-28\right)}}{2\times 6}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-14±\sqrt{196-4\times 6\left(-28\right)}}{2\times 6}
Square 14.
x=\frac{-14±\sqrt{196-24\left(-28\right)}}{2\times 6}
Multiply -4 times 6.
x=\frac{-14±\sqrt{196+672}}{2\times 6}
Multiply -24 times -28.
x=\frac{-14±\sqrt{868}}{2\times 6}
Add 196 to 672.
x=\frac{-14±2\sqrt{217}}{2\times 6}
Take the square root of 868.
x=\frac{-14±2\sqrt{217}}{12}
Multiply 2 times 6.
x=\frac{2\sqrt{217}-14}{12}
Now solve the equation x=\frac{-14±2\sqrt{217}}{12} when ± is plus. Add -14 to 2\sqrt{217}.
x=\frac{\sqrt{217}-7}{6}
Divide -14+2\sqrt{217} by 12.
x=\frac{-2\sqrt{217}-14}{12}
Now solve the equation x=\frac{-14±2\sqrt{217}}{12} when ± is minus. Subtract 2\sqrt{217} from -14.
x=\frac{-\sqrt{217}-7}{6}
Divide -14-2\sqrt{217} by 12.
6x^{2}+14x-28=6\left(x-\frac{\sqrt{217}-7}{6}\right)\left(x-\frac{-\sqrt{217}-7}{6}\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{-7+\sqrt{217}}{6} for x_{1} and \frac{-7-\sqrt{217}}{6} for x_{2}.