Solve 6*(11/8-5)+3^2

$$6 \times ( \frac { 11 } { 8 } - 5 ) + 3 ^ { 2 }$$

Evaluate

$$-\frac{51}{4}=-12.75$$

Solution Steps

Convert 5 to fraction \frac{40}{8}.

$$6\left(\frac{11}{8}-\frac{40}{8}\right)+3^{2}$$

Since \frac{11}{8} and \frac{40}{8} have the same denominator, subtract them by subtracting their numerators.

$$6\times \frac{11-40}{8}+3^{2}$$

Subtract 40 from 11 to get -29.

$$6\left(-\frac{29}{8}\right)+3^{2}$$

Express 6\left(-\frac{29}{8}\right) as a single fraction.

$$\frac{6\left(-29\right)}{8}+3^{2}$$

Multiply 6 and -29 to get -174.

$$\frac{-174}{8}+3^{2}$$

Reduce the fraction \frac{-174}{8} to lowest terms by extracting and canceling out 2.

$$-\frac{87}{4}+3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$-\frac{87}{4}+9$$

Convert 9 to fraction \frac{36}{4}.

$$-\frac{87}{4}+\frac{36}{4}$$

Since -\frac{87}{4} and \frac{36}{4} have the same denominator, add them by adding their numerators.

$$\frac{-87+36}{4}$$

Add -87 and 36 to get -51.

$$-\frac{51}{4}$$

Factor

$$-\frac{51}{4} = -12\frac{3}{4} = -12.75$$