Solve 6*-4^2-2*-4*-3+2*-3^2

$$6 \times - { 4 }^{ 2 } -2 \times -4 \times -3+2 \times - { 3 }^{ 2 }$$

Evaluate

$$-138$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$6\left(-16\right)-2\left(-4\right)\left(-3\right)+2\left(-3^{2}\right)$$

Multiply 6 and -16 to get -96.

$$-96-2\left(-4\right)\left(-3\right)+2\left(-3^{2}\right)$$

Multiply 2 and -4 to get -8.

$$-96-\left(-8\left(-3\right)\right)+2\left(-3^{2}\right)$$

Multiply -8 and -3 to get 24.

$$-96-24+2\left(-3^{2}\right)$$

Subtract 24 from -96 to get -120.

$$-120+2\left(-3^{2}\right)$$

Calculate 3 to the power of 2 and get 9.

$$-120+2\left(-9\right)$$

Multiply 2 and -9 to get -18.

$$-120-18$$

Subtract 18 from -120 to get -138.

$$-138$$

Factor

$$-138$$