Solve 6*8^2+1*8^1+7*8^0+7*8^-1

$$6 \times { 8 }^{ 2 } +1 \times { 8 }^{ 1 } +7 \times { 8 }^{ 0 } +7 \times { 8 }^{ -1 }$$

Evaluate

$$\frac{3199}{8}=399.875$$

Solution Steps

Calculate 8 to the power of 2 and get 64.

$$6\times 64+1\times 8^{1}+7\times 8^{0}+7\times 8^{-1}$$

Multiply 6 and 64 to get 384.

$$384+1\times 8^{1}+7\times 8^{0}+7\times 8^{-1}$$

Calculate 8 to the power of 1 and get 8.

$$384+1\times 8+7\times 8^{0}+7\times 8^{-1}$$

Multiply 1 and 8 to get 8.

$$384+8+7\times 8^{0}+7\times 8^{-1}$$

Add 384 and 8 to get 392.

$$392+7\times 8^{0}+7\times 8^{-1}$$

Calculate 8 to the power of 0 and get 1.

$$392+7\times 1+7\times 8^{-1}$$

Multiply 7 and 1 to get 7.

$$392+7+7\times 8^{-1}$$

Add 392 and 7 to get 399.

$$399+7\times 8^{-1}$$

Calculate 8 to the power of -1 and get \frac{1}{8}.

$$399+7\times \frac{1}{8}$$

Multiply 7 and \frac{1}{8} to get \frac{7}{8}.

$$399+\frac{7}{8}$$

Add 399 and \frac{7}{8} to get \frac{3199}{8}.

$$\frac{3199}{8}$$

Factor

$$\frac{7 \cdot 457}{2 ^ {3}} = 399\frac{7}{8} = 399.875$$