Solve 6*2/3+3/4-25/4

$$6 \times \frac{ 2 }{ 3 } + \frac{ 3 }{ 4 } - \frac{ 25 }{ 4 }$$

Evaluate

$$-\frac{3}{2}=-1.5$$

Solution Steps

Express 6\times \frac{2}{3} as a single fraction.

$$\frac{6\times 2}{3}+\frac{3}{4}-\frac{25}{4}$$

Multiply 6 and 2 to get 12.

$$\frac{12}{3}+\frac{3}{4}-\frac{25}{4}$$

Divide 12 by 3 to get 4.

$$4+\frac{3}{4}-\frac{25}{4}$$

Convert 4 to fraction \frac{16}{4}.

$$\frac{16}{4}+\frac{3}{4}-\frac{25}{4}$$

Since \frac{16}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{16+3}{4}-\frac{25}{4}$$

Add 16 and 3 to get 19.

$$\frac{19}{4}-\frac{25}{4}$$

Since \frac{19}{4} and \frac{25}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{19-25}{4}$$

Subtract 25 from 19 to get -6.

$$\frac{-6}{4}$$

Reduce the fraction \frac{-6}{4} to lowest terms by extracting and canceling out 2.

$$-\frac{3}{2}$$

Factor

$$-\frac{3}{2} = -1\frac{1}{2} = -1.5$$