Solve 64/10*48/12+640/16*-3/9}

$$6 \frac { 4 } { 10 } \times \frac { 48 } { 12 } + \frac { 640 } { 16 } \times \frac { - 3 } { 9 } \}$$

Evaluate

$$\frac{184}{15}\approx 12.266666667$$

Solution Steps

Multiply 6 and 10 to get 60.

$$\frac{60+4}{10}\times \frac{48}{12}+\frac{640}{16}\times \frac{-3}{9}$$

Add 60 and 4 to get 64.

$$\frac{64}{10}\times \frac{48}{12}+\frac{640}{16}\times \frac{-3}{9}$$

Reduce the fraction \frac{64}{10} to lowest terms by extracting and canceling out 2.

$$\frac{32}{5}\times \frac{48}{12}+\frac{640}{16}\times \frac{-3}{9}$$

Divide 48 by 12 to get 4.

$$\frac{32}{5}\times 4+\frac{640}{16}\times \frac{-3}{9}$$

Express \frac{32}{5}\times 4 as a single fraction.

$$\frac{32\times 4}{5}+\frac{640}{16}\times \frac{-3}{9}$$

Multiply 32 and 4 to get 128.

$$\frac{128}{5}+\frac{640}{16}\times \frac{-3}{9}$$

Divide 640 by 16 to get 40.

$$\frac{128}{5}+40\times \frac{-3}{9}$$

Reduce the fraction \frac{-3}{9} to lowest terms by extracting and canceling out 3.

$$\frac{128}{5}+40\left(-\frac{1}{3}\right)$$

Express 40\left(-\frac{1}{3}\right) as a single fraction.

$$\frac{128}{5}+\frac{40\left(-1\right)}{3}$$

Multiply 40 and -1 to get -40.

$$\frac{128}{5}+\frac{-40}{3}$$

Fraction \frac{-40}{3} can be rewritten as -\frac{40}{3} by extracting the negative sign.

$$\frac{128}{5}-\frac{40}{3}$$

Least common multiple of 5 and 3 is 15. Convert \frac{128}{5} and \frac{40}{3} to fractions with denominator 15.

$$\frac{384}{15}-\frac{200}{15}$$

Since \frac{384}{15} and \frac{200}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{384-200}{15}$$

Subtract 200 from 384 to get 184.

$$\frac{184}{15}$$

Factor

$$\frac{2 ^ {3} \cdot 23}{3 \cdot 5} = 12\frac{4}{15} = 12.266666666666667$$