Solve 63/8+25/6+15/12

$$6 \frac { 3 } { 8 } + 2 \frac { 5 } { 6 } + 1 \frac { 5 } { 12 }$$

Evaluate

$$\frac{85}{8}=10.625$$

Solution Steps

Multiply 6 and 8 to get 48.

$$\frac{48+3}{8}+\frac{2\times 6+5}{6}+\frac{1\times 12+5}{12}$$

Add 48 and 3 to get 51.

$$\frac{51}{8}+\frac{2\times 6+5}{6}+\frac{1\times 12+5}{12}$$

Multiply 2 and 6 to get 12.

$$\frac{51}{8}+\frac{12+5}{6}+\frac{1\times 12+5}{12}$$

Add 12 and 5 to get 17.

$$\frac{51}{8}+\frac{17}{6}+\frac{1\times 12+5}{12}$$

Least common multiple of 8 and 6 is 24. Convert \frac{51}{8} and \frac{17}{6} to fractions with denominator 24.

$$\frac{153}{24}+\frac{68}{24}+\frac{1\times 12+5}{12}$$

Since \frac{153}{24} and \frac{68}{24} have the same denominator, add them by adding their numerators.

$$\frac{153+68}{24}+\frac{1\times 12+5}{12}$$

Add 153 and 68 to get 221.

$$\frac{221}{24}+\frac{1\times 12+5}{12}$$

Multiply 1 and 12 to get 12.

$$\frac{221}{24}+\frac{12+5}{12}$$

Add 12 and 5 to get 17.

$$\frac{221}{24}+\frac{17}{12}$$

Least common multiple of 24 and 12 is 24. Convert \frac{221}{24} and \frac{17}{12} to fractions with denominator 24.

$$\frac{221}{24}+\frac{34}{24}$$

Since \frac{221}{24} and \frac{34}{24} have the same denominator, add them by adding their numerators.

$$\frac{221+34}{24}$$

Add 221 and 34 to get 255.

$$\frac{255}{24}$$

Reduce the fraction \frac{255}{24} to lowest terms by extracting and canceling out 3.

$$\frac{85}{8}$$

Factor

$$\frac{5 \cdot 17}{2 ^ {3}} = 10\frac{5}{8} = 10.625$$