Solve 63/4div3/2=

$$6 \frac { 3 } { 4 } \div \frac { 3 } { 2 } =$$

Evaluate

$$\frac{9}{2}=4.5$$

Solution Steps

Divide \frac{6\times 4+3}{4} by \frac{3}{2} by multiplying \frac{6\times 4+3}{4} by the reciprocal of \frac{3}{2}.

$$\frac{\left(6\times 4+3\right)\times 2}{4\times 3}$$

Cancel out 2 in both numerator and denominator.

$$\frac{3+4\times 6}{2\times 3}$$

Multiply 4 and 6 to get 24.

$$\frac{3+24}{2\times 3}$$

Add 3 and 24 to get 27.

$$\frac{27}{2\times 3}$$

Multiply 2 and 3 to get 6.

$$\frac{27}{6}$$

Reduce the fraction \frac{27}{6} to lowest terms by extracting and canceling out 3.

$$\frac{9}{2}$$

Factor

$$\frac{3 ^ {2}}{2} = 4\frac{1}{2} = 4.5$$