Solve 63/4*111/45=

$$6 \frac { 3 } { 4 } \cdot 1 \frac { 11 } { 45 } =$$

Evaluate

$$\frac{42}{5}=8.4$$

Solution Steps

Multiply 6 and 4 to get 24.

$$\frac{24+3}{4}\times \frac{1\times 45+11}{45}$$

Add 24 and 3 to get 27.

$$\frac{27}{4}\times \frac{1\times 45+11}{45}$$

Multiply 1 and 45 to get 45.

$$\frac{27}{4}\times \frac{45+11}{45}$$

Add 45 and 11 to get 56.

$$\frac{27}{4}\times \frac{56}{45}$$

Multiply \frac{27}{4} times \frac{56}{45} by multiplying numerator times numerator and denominator times denominator.

$$\frac{27\times 56}{4\times 45}$$

Do the multiplications in the fraction \frac{27\times 56}{4\times 45}.

$$\frac{1512}{180}$$

Reduce the fraction \frac{1512}{180} to lowest terms by extracting and canceling out 36.

$$\frac{42}{5}$$

Factor

$$\frac{2 \cdot 3 \cdot 7}{5} = 8\frac{2}{5} = 8.4$$