Solve 62/9+15/6-4=

$$6 \frac { 2 } { 9 } + 1 \frac { 5 } { 6 } - 4 =$$

Evaluate

$$\frac{73}{18}\approx 4.055555556$$

Solution Steps

Multiply 6 and 9 to get 54.

$$\frac{54+2}{9}+\frac{1\times 6+5}{6}-4$$

Add 54 and 2 to get 56.

$$\frac{56}{9}+\frac{1\times 6+5}{6}-4$$

Multiply 1 and 6 to get 6.

$$\frac{56}{9}+\frac{6+5}{6}-4$$

Add 6 and 5 to get 11.

$$\frac{56}{9}+\frac{11}{6}-4$$

Least common multiple of 9 and 6 is 18. Convert \frac{56}{9} and \frac{11}{6} to fractions with denominator 18.

$$\frac{112}{18}+\frac{33}{18}-4$$

Since \frac{112}{18} and \frac{33}{18} have the same denominator, add them by adding their numerators.

$$\frac{112+33}{18}-4$$

Add 112 and 33 to get 145.

$$\frac{145}{18}-4$$

Convert 4 to fraction \frac{72}{18}.

$$\frac{145}{18}-\frac{72}{18}$$

Since \frac{145}{18} and \frac{72}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{145-72}{18}$$

Subtract 72 from 145 to get 73.

$$\frac{73}{18}$$

Factor

$$\frac{73}{2 \cdot 3 ^ {2}} = 4\frac{1}{18} = 4.055555555555555$$