Solve 62/5-32/3=

$$6 \frac { 2 } { 5 } - 3 \frac { 2 } { 3 } =$$

Evaluate

$$\frac{41}{15}\approx 2.733333333$$

Solution Steps

Multiply 6 and 5 to get 30.

$$\frac{30+2}{5}-\frac{3\times 3+2}{3}$$

Add 30 and 2 to get 32.

$$\frac{32}{5}-\frac{3\times 3+2}{3}$$

Multiply 3 and 3 to get 9.

$$\frac{32}{5}-\frac{9+2}{3}$$

Add 9 and 2 to get 11.

$$\frac{32}{5}-\frac{11}{3}$$

Least common multiple of 5 and 3 is 15. Convert \frac{32}{5} and \frac{11}{3} to fractions with denominator 15.

$$\frac{96}{15}-\frac{55}{15}$$

Since \frac{96}{15} and \frac{55}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{96-55}{15}$$

Subtract 55 from 96 to get 41.

$$\frac{41}{15}$$

Factor

$$\frac{41}{3 \cdot 5} = 2\frac{11}{15} = 2.7333333333333334$$