Solve 62/5+31/3+1/2-7/10

$$6 \frac { 2 } { 5 } + 3 \frac { 1 } { 3 } + \frac { 1 } { 2 } - \frac { 7 } { 10 }$$

Evaluate

$$\frac{143}{15}\approx 9.533333333$$

Solution Steps

Multiply 6 and 5 to get 30.

$$\frac{30+2}{5}+\frac{3\times 3+1}{3}+\frac{1}{2}-\frac{7}{10}$$

Add 30 and 2 to get 32.

$$\frac{32}{5}+\frac{3\times 3+1}{3}+\frac{1}{2}-\frac{7}{10}$$

Multiply 3 and 3 to get 9.

$$\frac{32}{5}+\frac{9+1}{3}+\frac{1}{2}-\frac{7}{10}$$

Add 9 and 1 to get 10.

$$\frac{32}{5}+\frac{10}{3}+\frac{1}{2}-\frac{7}{10}$$

Least common multiple of 5 and 3 is 15. Convert \frac{32}{5} and \frac{10}{3} to fractions with denominator 15.

$$\frac{96}{15}+\frac{50}{15}+\frac{1}{2}-\frac{7}{10}$$

Since \frac{96}{15} and \frac{50}{15} have the same denominator, add them by adding their numerators.

$$\frac{96+50}{15}+\frac{1}{2}-\frac{7}{10}$$

Add 96 and 50 to get 146.

$$\frac{146}{15}+\frac{1}{2}-\frac{7}{10}$$

Least common multiple of 15 and 2 is 30. Convert \frac{146}{15} and \frac{1}{2} to fractions with denominator 30.

$$\frac{292}{30}+\frac{15}{30}-\frac{7}{10}$$

Since \frac{292}{30} and \frac{15}{30} have the same denominator, add them by adding their numerators.

$$\frac{292+15}{30}-\frac{7}{10}$$

Add 292 and 15 to get 307.

$$\frac{307}{30}-\frac{7}{10}$$

Least common multiple of 30 and 10 is 30. Convert \frac{307}{30} and \frac{7}{10} to fractions with denominator 30.

$$\frac{307}{30}-\frac{21}{30}$$

Since \frac{307}{30} and \frac{21}{30} have the same denominator, subtract them by subtracting their numerators.

$$\frac{307-21}{30}$$

Subtract 21 from 307 to get 286.

$$\frac{286}{30}$$

Reduce the fraction \frac{286}{30} to lowest terms by extracting and canceling out 2.

$$\frac{143}{15}$$

Factor

$$\frac{11 \cdot 13}{3 \cdot 5} = 9\frac{8}{15} = 9.533333333333333$$