Solve 62/3*33/11

$$6 \frac { 2 } { 3 } \times 3 \frac { 3 } { 11 }$$

Evaluate

$$\frac{240}{11}\approx 21.818181818$$

Solution Steps

Multiply 6 and 3 to get 18.

$$\frac{18+2}{3}\times \frac{3\times 11+3}{11}$$

Add 18 and 2 to get 20.

$$\frac{20}{3}\times \frac{3\times 11+3}{11}$$

Multiply 3 and 11 to get 33.

$$\frac{20}{3}\times \frac{33+3}{11}$$

Add 33 and 3 to get 36.

$$\frac{20}{3}\times \frac{36}{11}$$

Multiply \frac{20}{3} times \frac{36}{11} by multiplying numerator times numerator and denominator times denominator.

$$\frac{20\times 36}{3\times 11}$$

Do the multiplications in the fraction \frac{20\times 36}{3\times 11}.

$$\frac{720}{33}$$

Reduce the fraction \frac{720}{33} to lowest terms by extracting and canceling out 3.

$$\frac{240}{11}$$

Factor

$$\frac{2 ^ {4} \cdot 3 \cdot 5}{11} = 21\frac{9}{11} = 21.818181818181817$$