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\frac{\left(6\times 3+2\right)\times 2}{3\left(7\times 2+1\right)}
Divide \frac{6\times 3+2}{3} by \frac{7\times 2+1}{2} by multiplying \frac{6\times 3+2}{3} by the reciprocal of \frac{7\times 2+1}{2}.
\frac{\left(18+2\right)\times 2}{3\left(7\times 2+1\right)}
Multiply 6 and 3 to get 18.
\frac{20\times 2}{3\left(7\times 2+1\right)}
Add 18 and 2 to get 20.
\frac{40}{3\left(7\times 2+1\right)}
Multiply 20 and 2 to get 40.
\frac{40}{3\left(14+1\right)}
Multiply 7 and 2 to get 14.
\frac{40}{3\times 15}
Add 14 and 1 to get 15.
\frac{40}{45}
Multiply 3 and 15 to get 45.
\frac{8}{9}
Reduce the fraction \frac{40}{45} to lowest terms by extracting and canceling out 5.