Solve 611/12-(24/16+32/3)

$$6 \frac { 11 } { 12 } - ( 2 \frac { 4 } { 16 } + 3 \frac { 2 } { 3 } )$$

Evaluate

$$1$$

Solution Steps

Multiply 6 and 12 to get 72.

$$\frac{72+11}{12}-\left(\frac{2\times 16+4}{16}+\frac{3\times 3+2}{3}\right)$$

Add 72 and 11 to get 83.

$$\frac{83}{12}-\left(\frac{2\times 16+4}{16}+\frac{3\times 3+2}{3}\right)$$

Multiply 2 and 16 to get 32.

$$\frac{83}{12}-\left(\frac{32+4}{16}+\frac{3\times 3+2}{3}\right)$$

Add 32 and 4 to get 36.

$$\frac{83}{12}-\left(\frac{36}{16}+\frac{3\times 3+2}{3}\right)$$

Reduce the fraction \frac{36}{16} to lowest terms by extracting and canceling out 4.

$$\frac{83}{12}-\left(\frac{9}{4}+\frac{3\times 3+2}{3}\right)$$

Multiply 3 and 3 to get 9.

$$\frac{83}{12}-\left(\frac{9}{4}+\frac{9+2}{3}\right)$$

Add 9 and 2 to get 11.

$$\frac{83}{12}-\left(\frac{9}{4}+\frac{11}{3}\right)$$

Least common multiple of 4 and 3 is 12. Convert \frac{9}{4} and \frac{11}{3} to fractions with denominator 12.

$$\frac{83}{12}-\left(\frac{27}{12}+\frac{44}{12}\right)$$

Since \frac{27}{12} and \frac{44}{12} have the same denominator, add them by adding their numerators.

$$\frac{83}{12}-\frac{27+44}{12}$$

Add 27 and 44 to get 71.

$$\frac{83}{12}-\frac{71}{12}$$

Since \frac{83}{12} and \frac{71}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{83-71}{12}$$

Subtract 71 from 83 to get 12.

$$\frac{12}{12}$$

Divide 12 by 12 to get 1.

$$1$$

Factor

$$1$$