Solve 61/5div(21/3-4/15)

$$6 \frac { 1 } { 5 } \div ( 2 \frac { 1 } { 3 } - \frac { 4 } { 15 } )$$

Evaluate

$$3$$

Solution Steps

Multiply 6 and 5 to get 30.

$$\frac{\frac{30+1}{5}}{\frac{2\times 3+1}{3}-\frac{4}{15}}$$

Add 30 and 1 to get 31.

$$\frac{\frac{31}{5}}{\frac{2\times 3+1}{3}-\frac{4}{15}}$$

Multiply 2 and 3 to get 6.

$$\frac{\frac{31}{5}}{\frac{6+1}{3}-\frac{4}{15}}$$

Add 6 and 1 to get 7.

$$\frac{\frac{31}{5}}{\frac{7}{3}-\frac{4}{15}}$$

Least common multiple of 3 and 15 is 15. Convert \frac{7}{3} and \frac{4}{15} to fractions with denominator 15.

$$\frac{\frac{31}{5}}{\frac{35}{15}-\frac{4}{15}}$$

Since \frac{35}{15} and \frac{4}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{31}{5}}{\frac{35-4}{15}}$$

Subtract 4 from 35 to get 31.

$$\frac{\frac{31}{5}}{\frac{31}{15}}$$

Divide \frac{31}{5} by \frac{31}{15} by multiplying \frac{31}{5} by the reciprocal of \frac{31}{15}.

$$\frac{31}{5}\times \frac{15}{31}$$

Multiply \frac{31}{5} times \frac{15}{31} by multiplying numerator times numerator and denominator times denominator.

$$\frac{31\times 15}{5\times 31}$$

Cancel out 31 in both numerator and denominator.

$$\frac{15}{5}$$

Divide 15 by 5 to get 3.

$$3$$

Factor

$$3$$