Solve 61/3+42/6

$$6 \frac { 1 } { 3 } + 4 \frac { 2 } { 6 }$$

Evaluate

$$\frac{32}{3}\approx 10.666666667$$

Solution Steps

Multiply 6 and 3 to get 18.

$$\frac{18+1}{3}+\frac{4\times 6+2}{6}$$

Add 18 and 1 to get 19.

$$\frac{19}{3}+\frac{4\times 6+2}{6}$$

Multiply 4 and 6 to get 24.

$$\frac{19}{3}+\frac{24+2}{6}$$

Add 24 and 2 to get 26.

$$\frac{19}{3}+\frac{26}{6}$$

Reduce the fraction \frac{26}{6} to lowest terms by extracting and canceling out 2.

$$\frac{19}{3}+\frac{13}{3}$$

Since \frac{19}{3} and \frac{13}{3} have the same denominator, add them by adding their numerators.

$$\frac{19+13}{3}$$

Add 19 and 13 to get 32.

$$\frac{32}{3}$$

Factor

$$\frac{2 ^ {5}}{3} = 10\frac{2}{3} = 10.666666666666666$$