Solve 61/3+24/9-11*7/8

$$6 \frac { 1 } { 3 } + 2 \frac { 4 } { 9 } - 11 \times \frac { 7 } { 8 }$$

Evaluate

$$-\frac{61}{72}\approx -0.847222222$$

Solution Steps

Multiply 6 and 3 to get 18.

$$\frac{18+1}{3}+\frac{2\times 9+4}{9}-11\times \frac{7}{8}$$

Add 18 and 1 to get 19.

$$\frac{19}{3}+\frac{2\times 9+4}{9}-11\times \frac{7}{8}$$

Multiply 2 and 9 to get 18.

$$\frac{19}{3}+\frac{18+4}{9}-11\times \frac{7}{8}$$

Add 18 and 4 to get 22.

$$\frac{19}{3}+\frac{22}{9}-11\times \frac{7}{8}$$

Least common multiple of 3 and 9 is 9. Convert \frac{19}{3} and \frac{22}{9} to fractions with denominator 9.

$$\frac{57}{9}+\frac{22}{9}-11\times \frac{7}{8}$$

Since \frac{57}{9} and \frac{22}{9} have the same denominator, add them by adding their numerators.

$$\frac{57+22}{9}-11\times \frac{7}{8}$$

Add 57 and 22 to get 79.

$$\frac{79}{9}-11\times \frac{7}{8}$$

Express 11\times \frac{7}{8} as a single fraction.

$$\frac{79}{9}-\frac{11\times 7}{8}$$

Multiply 11 and 7 to get 77.

$$\frac{79}{9}-\frac{77}{8}$$

Least common multiple of 9 and 8 is 72. Convert \frac{79}{9} and \frac{77}{8} to fractions with denominator 72.

$$\frac{632}{72}-\frac{693}{72}$$

Since \frac{632}{72} and \frac{693}{72} have the same denominator, subtract them by subtracting their numerators.

$$\frac{632-693}{72}$$

Subtract 693 from 632 to get -61.

$$-\frac{61}{72}$$

Factor

$$-\frac{61}{72} = -0.8472222222222222$$