Solve 6div(-2)^3-(-1/2)^3*(-4)-(-1)^2

$$6 \div ( - 2 ) ^ { 3 } - ( - \frac { 1 } { 2 } ) ^ { 3 } \times ( - 4 ) - ( - 1 ) ^ { 2 }$$

Evaluate

$$-\frac{9}{4}=-2.25$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$\frac{6}{-8}-\left(-\frac{1}{2}\right)^{3}\left(-4\right)-\left(-1\right)^{2}$$

Reduce the fraction \frac{6}{-8} to lowest terms by extracting and canceling out 2.

$$-\frac{3}{4}-\left(-\frac{1}{2}\right)^{3}\left(-4\right)-\left(-1\right)^{2}$$

Calculate -\frac{1}{2} to the power of 3 and get -\frac{1}{8}.

$$-\frac{3}{4}-\left(-\frac{1}{8}\left(-4\right)\right)-\left(-1\right)^{2}$$

Express -\frac{1}{8}\left(-4\right) as a single fraction.

$$-\frac{3}{4}-\frac{-\left(-4\right)}{8}-\left(-1\right)^{2}$$

Multiply -1 and -4 to get 4.

$$-\frac{3}{4}-\frac{4}{8}-\left(-1\right)^{2}$$

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$-\frac{3}{4}-\frac{1}{2}-\left(-1\right)^{2}$$

Least common multiple of 4 and 2 is 4. Convert -\frac{3}{4} and \frac{1}{2} to fractions with denominator 4.

$$-\frac{3}{4}-\frac{2}{4}-\left(-1\right)^{2}$$

Since -\frac{3}{4} and \frac{2}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-3-2}{4}-\left(-1\right)^{2}$$

Subtract 2 from -3 to get -5.

$$-\frac{5}{4}-\left(-1\right)^{2}$$

Calculate -1 to the power of 2 and get 1.

$$-\frac{5}{4}-1$$

Convert 1 to fraction \frac{4}{4}.

$$-\frac{5}{4}-\frac{4}{4}$$

Since -\frac{5}{4} and \frac{4}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-5-4}{4}$$

Subtract 4 from -5 to get -9.

$$-\frac{9}{4}$$

Factor

$$-\frac{9}{4} = -2\frac{1}{4} = -2.25$$