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\frac{6\sqrt{2}}{\left(\sqrt{2}\right)^{2}}\times \frac{2}{\sqrt{2}}=b
Rationalize the denominator of \frac{6}{\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{6\sqrt{2}}{2}\times \frac{2}{\sqrt{2}}=b
The square of \sqrt{2} is 2.
3\sqrt{2}\times \frac{2}{\sqrt{2}}=b
Divide 6\sqrt{2} by 2 to get 3\sqrt{2}.
3\sqrt{2}\times \frac{2\sqrt{2}}{\left(\sqrt{2}\right)^{2}}=b
Rationalize the denominator of \frac{2}{\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
3\sqrt{2}\times \frac{2\sqrt{2}}{2}=b
The square of \sqrt{2} is 2.
3\sqrt{2}\sqrt{2}=b
Cancel out 2 and 2.
3\times 2=b
Multiply \sqrt{2} and \sqrt{2} to get 2.
6=b
Multiply 3 and 2 to get 6.
b=6
Swap sides so that all variable terms are on the left hand side.