Solve 6divx+21divx+45divx+12+21divx

$$6 \div x+21 \div x+45 \div x+12+21 \div x$$

Evaluate

$$12+\frac{93}{x}$$

Short Solution Steps

Combine \frac{21}{x} and \frac{21}{x} to get 2\times \frac{21}{x}.

$$\frac{6}{x}+2\times \frac{21}{x}+\frac{45}{x}+12$$

Since \frac{6}{x} and \frac{45}{x} have the same denominator, add them by adding their numerators. Add 6 and 45 to get 51.

$$\frac{51}{x}+2\times \frac{21}{x}+12$$

Express 2\times \frac{21}{x} as a single fraction.

$$\frac{6}{x}+\frac{2\times 21}{x}+\frac{45}{x}+12$$

Since \frac{6}{x} and \frac{2\times 21}{x} have the same denominator, add them by adding their numerators.

$$\frac{6+2\times 21}{x}+\frac{45}{x}+12$$

Do the multiplications in 6+2\times 21.

$$\frac{6+42}{x}+\frac{45}{x}+12$$

Do the calculations in 6+42.

$$\frac{48}{x}+\frac{45}{x}+12$$

Since \frac{48}{x} and \frac{45}{x} have the same denominator, add them by adding their numerators. Add 48 and 45 to get 93.

$$\frac{93}{x}+12$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 12 times \frac{x}{x}.

$$\frac{93}{x}+\frac{12x}{x}$$

Since \frac{93}{x} and \frac{12x}{x} have the same denominator, add them by adding their numerators.

$$\frac{93+12x}{x}$$

Factor

$$\frac{3\left(4x+31\right)}{x}$$