Solve 6*8*(x-y)=40%(x+y)

$$6 \cdot 8 \cdot ( x - y ) = 40 \% ( x + y )$$

Solve for x

$$x=\frac{121y}{119}$$

Steps for Solving Linear Equation

Multiply 6 and 8 to get 48.

$$48\left(x-y\right)=\frac{40}{100}\left(x+y\right)$$

Use the distributive property to multiply 48 by x-y.

$$48x-48y=\frac{40}{100}\left(x+y\right)$$

Reduce the fraction \frac{40}{100} to lowest terms by extracting and canceling out 20.

$$48x-48y=\frac{2}{5}\left(x+y\right)$$

Use the distributive property to multiply \frac{2}{5} by x+y.

$$48x-48y=\frac{2}{5}x+\frac{2}{5}y$$

Subtract \frac{2}{5}x from both sides.

$$48x-48y-\frac{2}{5}x=\frac{2}{5}y$$

Combine 48x and -\frac{2}{5}x to get \frac{238}{5}x.

$$\frac{238}{5}x-48y=\frac{2}{5}y$$

Add 48y to both sides.

$$\frac{238}{5}x=\frac{2}{5}y+48y$$

Combine \frac{2}{5}y and 48y to get \frac{242}{5}y.

$$\frac{238}{5}x=\frac{242}{5}y$$

The equation is in standard form.

$$\frac{238}{5}x=\frac{242y}{5}$$

Divide both sides of the equation by \frac{238}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{238}{5}x}{\frac{238}{5}}=\frac{242y}{5\times \frac{238}{5}}$$

Dividing by \frac{238}{5} undoes the multiplication by \frac{238}{5}.

$$x=\frac{242y}{5\times \frac{238}{5}}$$

Divide \frac{242y}{5} by \frac{238}{5} by multiplying \frac{242y}{5} by the reciprocal of \frac{238}{5}.

$$x=\frac{121y}{119}$$

Solve for y

$$y=\frac{119x}{121}$$

Steps for Solving Linear Equation

Multiply 6 and 8 to get 48.

$$48\left(x-y\right)=\frac{40}{100}\left(x+y\right)$$

Use the distributive property to multiply 48 by x-y.

$$48x-48y=\frac{40}{100}\left(x+y\right)$$

Reduce the fraction \frac{40}{100} to lowest terms by extracting and canceling out 20.

$$48x-48y=\frac{2}{5}\left(x+y\right)$$

Use the distributive property to multiply \frac{2}{5} by x+y.

$$48x-48y=\frac{2}{5}x+\frac{2}{5}y$$

Subtract \frac{2}{5}y from both sides.

$$48x-48y-\frac{2}{5}y=\frac{2}{5}x$$

Combine -48y and -\frac{2}{5}y to get -\frac{242}{5}y.

$$48x-\frac{242}{5}y=\frac{2}{5}x$$

Subtract 48x from both sides.

$$-\frac{242}{5}y=\frac{2}{5}x-48x$$

Combine \frac{2}{5}x and -48x to get -\frac{238}{5}x.

$$-\frac{242}{5}y=-\frac{238}{5}x$$

The equation is in standard form.

$$-\frac{242}{5}y=-\frac{238x}{5}$$

Divide both sides of the equation by -\frac{242}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{242}{5}y}{-\frac{242}{5}}=-\frac{\frac{238x}{5}}{-\frac{242}{5}}$$

Dividing by -\frac{242}{5} undoes the multiplication by -\frac{242}{5}.

$$y=-\frac{\frac{238x}{5}}{-\frac{242}{5}}$$

Divide -\frac{238x}{5} by -\frac{242}{5} by multiplying -\frac{238x}{5} by the reciprocal of -\frac{242}{5}.

$$y=\frac{119x}{121}$$