Solve 6*5*(2+3)+5+3*4-(6-8)*(-2)=

$$6 \cdot 5 \cdot ( 2 + 3 ) + 5 + 3 \cdot 4 - ( 6 - 8 ) \cdot ( - 2 ) =$$

Evaluate

$$163$$

Solution Steps

Multiply 6 and 5 to get 30. Multiply 3 and 4 to get 12.

$$30\left(2+3\right)+5+12-\left(6-8\right)\left(-2\right)$$

Add 2 and 3 to get 5.

$$30\times 5+5+12-\left(6-8\right)\left(-2\right)$$

Multiply 30 and 5 to get 150.

$$150+5+12-\left(6-8\right)\left(-2\right)$$

Add 150 and 5 to get 155.

$$155+12-\left(6-8\right)\left(-2\right)$$

Add 155 and 12 to get 167.

$$167-\left(6-8\right)\left(-2\right)$$

Subtract 8 from 6 to get -2.

$$167-\left(-2\left(-2\right)\right)$$

Multiply -2 and -2 to get 4.

$$167-4$$

Subtract 4 from 167 to get 163.

$$163$$

Factor

$$163$$