Solve 6*4div8-18div3^2+(20div4)div(10div2)+91div7=

$$6 \cdot 4 \div 8 - 18 \div 3 ^ { 2 } + ( 20 \div 4 ) \div ( 10 \div 2 ) + 91 \div 7 =$$

Evaluate

$$15$$

Solution Steps

Multiply 6 and 4 to get 24.

$$\frac{24}{8}-\frac{18}{3^{2}}+\frac{\frac{20}{4}}{\frac{10}{2}}+\frac{91}{7}$$

Divide 24 by 8 to get 3.

$$3-\frac{18}{3^{2}}+\frac{\frac{20}{4}}{\frac{10}{2}}+\frac{91}{7}$$

Calculate 3 to the power of 2 and get 9.

$$3-\frac{18}{9}+\frac{\frac{20}{4}}{\frac{10}{2}}+\frac{91}{7}$$

Divide 18 by 9 to get 2.

$$3-2+\frac{\frac{20}{4}}{\frac{10}{2}}+\frac{91}{7}$$

Subtract 2 from 3 to get 1.

$$1+\frac{\frac{20}{4}}{\frac{10}{2}}+\frac{91}{7}$$

Divide \frac{20}{4} by \frac{10}{2} by multiplying \frac{20}{4} by the reciprocal of \frac{10}{2}.

$$1+\frac{20\times 2}{4\times 10}+\frac{91}{7}$$

Cancel out 2\times 4\times 5 in both numerator and denominator.

$$1+1+\frac{91}{7}$$

Add 1 and 1 to get 2.

$$2+\frac{91}{7}$$

Divide 91 by 7 to get 13.

$$2+13$$

Add 2 and 13 to get 15.

$$15$$

Factor

$$3\times 5$$