Solve 6*(120div4div6)-4^2-(8-3)*(12div2)+6sqrt{49}+8^0-10=

$$6 \cdot ( 120 \div 4 \div 6 ) - 4 ^ { 2 } - ( 8 - 3 ) \cdot ( 12 \div 2 ) + 6 \sqrt { 49 } + 8 ^ { 0 } - 10 =$$

Evaluate

$$17$$

Solution Steps

Express \frac{\frac{120}{4}}{6} as a single fraction.

$$6\times \frac{120}{4\times 6}-4^{2}-\left(8-3\right)\times \frac{12}{2}+6\sqrt{49}+8^{0}-10$$

Multiply 4 and 6 to get 24.

$$6\times \frac{120}{24}-4^{2}-\left(8-3\right)\times \frac{12}{2}+6\sqrt{49}+8^{0}-10$$

Divide 120 by 24 to get 5.

$$6\times 5-4^{2}-\left(8-3\right)\times \frac{12}{2}+6\sqrt{49}+8^{0}-10$$

Multiply 6 and 5 to get 30.

$$30-4^{2}-\left(8-3\right)\times \frac{12}{2}+6\sqrt{49}+8^{0}-10$$

Calculate 4 to the power of 2 and get 16.

$$30-16-\left(8-3\right)\times \frac{12}{2}+6\sqrt{49}+8^{0}-10$$

Subtract 16 from 30 to get 14.

$$14-\left(8-3\right)\times \frac{12}{2}+6\sqrt{49}+8^{0}-10$$

Subtract 3 from 8 to get 5.

$$14-5\times \frac{12}{2}+6\sqrt{49}+8^{0}-10$$

Divide 12 by 2 to get 6.

$$14-5\times 6+6\sqrt{49}+8^{0}-10$$

Multiply 5 and 6 to get 30.

$$14-30+6\sqrt{49}+8^{0}-10$$

Subtract 30 from 14 to get -16.

$$-16+6\sqrt{49}+8^{0}-10$$

Calculate the square root of 49 and get 7.

$$-16+6\times 7+8^{0}-10$$

Multiply 6 and 7 to get 42.

$$-16+42+8^{0}-10$$

Add -16 and 42 to get 26.

$$26+8^{0}-10$$

Calculate 8 to the power of 0 and get 1.

$$26+1-10$$

Add 26 and 1 to get 27.

$$27-10$$

Subtract 10 from 27 to get 17.

$$17$$

Factor

$$17$$