Solve 6*(-2)^3+7*-2*4*-2*2*2

$$6 \cdot ( - 2 ) ^ { 3 } + 7 \cdot - 2 \cdot 4 \cdot - 2 \cdot 2 \cdot 2$$

Evaluate

$$400$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$6\left(-8\right)+7\left(-2\right)\times 4\left(-2\right)\times 2\times 2$$

Multiply 6 and -8 to get -48.

$$-48+7\left(-2\right)\times 4\left(-2\right)\times 2\times 2$$

Multiply 7 and -2 to get -14.

$$-48-14\times 4\left(-2\right)\times 2\times 2$$

Multiply -14 and 4 to get -56.

$$-48-56\left(-2\right)\times 2\times 2$$

Multiply -56 and -2 to get 112.

$$-48+112\times 2\times 2$$

Multiply 112 and 2 to get 224.

$$-48+224\times 2$$

Multiply 224 and 2 to get 448.

$$-48+448$$

Add -48 and 448 to get 400.

$$400$$

Factor

$$2^{4}\times 5^{2}$$