Solve 6*(-frac{sqrt{3}}{3})^2

$$6 \cdot ( - \frac { \sqrt { 3 } } { 3 } ) ^ { 2 }$$

Evaluate

$$2$$

Solution Steps

Calculate -\frac{\sqrt{3}}{3} to the power of 2 and get \left(\frac{\sqrt{3}}{3}\right)^{2}.

$$6\times \left(\frac{\sqrt{3}}{3}\right)^{2}$$

To raise \frac{\sqrt{3}}{3} to a power, raise both numerator and denominator to the power and then divide.

$$6\times \frac{\left(\sqrt{3}\right)^{2}}{3^{2}}$$

Express 6\times \frac{\left(\sqrt{3}\right)^{2}}{3^{2}} as a single fraction.

$$\frac{6\left(\sqrt{3}\right)^{2}}{3^{2}}$$

The square of \sqrt{3} is 3.

$$\frac{6\times 3}{3^{2}}$$

Multiply 6 and 3 to get 18.

$$\frac{18}{3^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{18}{9}$$

Divide 18 by 9 to get 2.

$$2$$

Factor

$$2$$